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Estimate gravitational acceleration from video data | IB Physics Practice | Physics Insight
IB Physics/A.1 Kinematics/Question

Question pattern: Kinematics data analysis

Original question 2 of 2 in this pattern

HardEvaluate & predict7 marks10 minutes

Estimate gravitational acceleration from video data

A ball is released from rest and filmed as it falls. Downward displacement is measured from the release point. Each displacement has uncertainty ±0.005 m and each time has uncertainty ±0.005 s. Assume the model y = 1/2 gt².

a) Use the t = 0.400 s reading to estimate g.

b) Estimate the percentage uncertainty in g using percentage uncertainty in y plus twice the percentage uncertainty in t. Give an absolute uncertainty.

c) State whether the result is consistent with g = 9.81 m s⁻².

d) Explain why later frames usually give a more precise estimate than the earliest non-zero frame.

e) Identify two limitations of this video method or of the stated model.

Displacement plotted against time squared
Displacement plotted against time squaredScatter plot of downward displacement against time squared using the five video measurements.00.040.080.120.1600.20.40.60.8Time squared, t² / s²Downward displacement, y / m
Video measurements
Time / sDownward displacement / m
0.0000.000
0.1000.051
0.2000.194
0.3000.447
0.4000.780
Hint

Rearrange the model to g = 2y/t². For uncertainty, use δg/g ≈ δy/y + 2δt/t.

Worked answer

Solution

Model from the 0.400 s estimate
Model from the 0.400 s estimateDisplacement versus time squared data with the model line y equals four point eight seven five t squared, corresponding to g equals nine point seven five metres per second squared.00.040.080.120.1600.20.40.60.8Time squared, t² / s²Downward displacement, y / mVideo measurementsModel: y = 4.875t²
  1. Step 1

    At 0.400 s, g = 2y / t² = 2(0.780) / 0.400² = 9.75 m s⁻².

  2. Step 2

    Percentage uncertainty from displacement: 0.005 / 0.780 × 100% = 0.64%.

  3. Step 3

    Time contribution: 2(0.005 / 0.400) × 100% = 2.50%. Total approximate percentage uncertainty: 3.14%.

  4. Step 4

    Absolute uncertainty: 0.0314 × 9.75 = 0.31 m s⁻², so g ≈ (9.8 ± 0.3) m s⁻².

  5. Step 5

    The interval 9.5–10.1 m s⁻² contains 9.81 m s⁻², so the estimate is consistent with the stated value.

  6. Step 6

    Later frames have larger t and y, making the fixed absolute timing and position uncertainties smaller percentages of the measured quantities.

  7. Step 7

    Valid limitations include uncertainty in the exact release frame, parallax or scale calibration, camera perspective, frame-rate timing error, initial push, or fluid resistance making the constant-g model imperfect.

Final answer

g = 9.75 m s⁻² with approximate uncertainty 0.31 m s⁻², reported as (9.8 ± 0.3) m s⁻²; this is consistent with 9.81 m s⁻².

Common mistake

Using only the percentage uncertainty in displacement and forgetting that the time is squared.

Concepts tested

  • video analysis
  • gravitational acceleration
  • percentage uncertainty
  • model limitation

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